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Considere os conjuntos X={2,4,6,8,10}X=\{2,4,6,8,10\}X={2,4,6,8,10} * e Y={2,4,8,16,32}Y=\{2,4,8,16,32\}Y={2,4,8,16,32}. Se A=X∩YA=X \cap YA=X∩Y e B=XB=XB=X ∪Y\cup Y∪Y, pode-se afirmar que A={6,10}A=\{6,10\}A={6,10} e B={2,4,8}B=\{2,4,8\}B={2,4,8}. A={2,4,8}A=\{2,4,8\}A={2,4,8} e B={2,4,6,8,10,16,32}B=\{2,4,6,8,10,16,32\}B={2,4,6,8,10,16,32}. A={6,10,16,32}A=\{6,10,16,32\}A={6,10,16,32} e B={2,4,6,8,10,16B=\{2,4,6,8,10,16B={2,4,6,8,10,16, 32}32\}32}. A={2,4,8}A=\{2,4,8\}A={2,4,8} e B={2,2,4,4,6,8,8,10,16B=\{2,2,4,4,6,8,8,10,16B={2,2,4,4,6,8,8,10,16, 32}32\}32}.
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