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Engenharia de Produção ·
Química Analítica
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Guilherme Santanna Creggario 4EX 242012 Química Analítica Qualitativa e Quantitativa Atividade 1 1. ( 3 c ) Reações com base forte em excesso | | B2+2 + N H4 O H(f) [ C ( N H4 ) 2 ] 2 - [ Z n ( OH ) 2 ] ( s ) \u21e3 ( ou ) [ B2 ( OH ) 2 ] ( aq ) Regências com base pouco em excesso ( [ C U ( I I ) 2 ] 2 - [ Z n ( O H ) 4 ] ( aq ) \u21e3 [ Z n ( O H ) 2 ] ( s ) [ ( C U ( I I )2 ] 2 [ C U ( N H ) 2 ] 2 + ( N H4 O H ) + | \u21e3 2 e. -ppto Castanho ( 2 ) - \u21e3 H + - Solução amarelada ( 3 ) + | F e 3+ 2 H + - Solução verde ( 5 ) ( N I : + 2 3 ) 3 . ( 1 F ) B2 ( P O4 ) 2 K P s : j 3 . 10 - 23 a . B2 ( P O4 ) 2 \u21e3 3 P O 4 3 - 2 P O 4 3 - 5 . 3 5 K Ps = 2 . 3 . 10 - 25 b . K Ps = [ B2 + 2 ] 2 [ P O4 3 - ] 2 c kps: [ 3 9 7 2 ( 2 5 8 ) ] kP2 = 3 5 .5 kP3 = 3 6 . 5 S = 5 1 3 . 10 - 7 / 3 6 S : 8 . 2 . 10 - 7 mol / L d S = S : 8 . 2 . 10 - 7 mol / L H2 S B 2 = 3 s : 2 4 . 10 - 6 mol / L 5 P2 : = 2 s : 4 . 6 . 10 - 6 mol / L e. B2 3( PO4)2 MM = 3 * 37 . 3 + 2 * 30 . 9 + 9 * 16 - 60 . 8 4 g / mol S B 2 3 (P O4)2 = 8 . 2 . 10 - 7 * 601 . 84 * 1 . 10 - 3 mg/L mol / g _ y (s) B2 3 (P O4)2 = 0 . 49 ppm 4 ( C . 9 ) a. Cl2 Fe ( CN6 ) I 2 \u21e3 2 ( Cl2 + ( Fe ( CN6 ) ) s 0 . 5 s b kB = [ Cl2 ] 2 [ Fe( CN6 ) ] C . 2 . 10 - 13 = ( 2 5 ) 2 5 3 . 2 . 10 - 15 B0 = 2 . 10 - 7 = 2 . 10 - 6 mol / L d S = 2 . 10 - 6 mol / L Cl2 ( Fe ( CN6 ) ) 3 cd = 2 5 : 9 . 10 - 6 mol / L S = S : 2 . 10 - 6 mol / L e. MM = 2 * 1 . 12 + 41 * 55 . 85 - 6 * 12 + 6 * 14 . 01 = 436 . 79 g / mol S = 2 . 10 - 6 mL * 436 . 79 g / mol * 1 . 10 - 3 mg = 0 . 87 mg L _ -1 S Fe (CN)7 = 4 . 9 7 ppm 5 . ( 3 C ) B2( OH)2 \u21e3 B a2 + 2 0 H - ( aq ) K Ps = [ B a2 + ] [ OH - ] 2 K Ps = 5 . ( 0 2 5 ) 2 K Ps = 5 . 4 5 2 K Ps = 4 . ( 0 1 0 ) 3 K Ps = 5 . 1 8 . 10 - 3 6 . 1 . 3 e . A g 3 - P Q 3 \u21e3 3 A g + + P O 4 - 2 K Ps = 9 ( 2 . 7 . 10 - 6 ) 2 K Ps = ( 3 ) 3 . ( 5 ) K Ps = 9 . 6 K Ps = 4 . 8 . 10 - 7
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Guilherme Santanna Creggario 4EX 242012 Química Analítica Qualitativa e Quantitativa Atividade 1 1. ( 3 c ) Reações com base forte em excesso | | B2+2 + N H4 O H(f) [ C ( N H4 ) 2 ] 2 - [ Z n ( OH ) 2 ] ( s ) \u21e3 ( ou ) [ B2 ( OH ) 2 ] ( aq ) Regências com base pouco em excesso ( [ C U ( I I ) 2 ] 2 - [ Z n ( O H ) 4 ] ( aq ) \u21e3 [ Z n ( O H ) 2 ] ( s ) [ ( C U ( I I )2 ] 2 [ C U ( N H ) 2 ] 2 + ( N H4 O H ) + | \u21e3 2 e. -ppto Castanho ( 2 ) - \u21e3 H + - Solução amarelada ( 3 ) + | F e 3+ 2 H + - Solução verde ( 5 ) ( N I : + 2 3 ) 3 . ( 1 F ) B2 ( P O4 ) 2 K P s : j 3 . 10 - 23 a . B2 ( P O4 ) 2 \u21e3 3 P O 4 3 - 2 P O 4 3 - 5 . 3 5 K Ps = 2 . 3 . 10 - 25 b . K Ps = [ B2 + 2 ] 2 [ P O4 3 - ] 2 c kps: [ 3 9 7 2 ( 2 5 8 ) ] kP2 = 3 5 .5 kP3 = 3 6 . 5 S = 5 1 3 . 10 - 7 / 3 6 S : 8 . 2 . 10 - 7 mol / L d S = S : 8 . 2 . 10 - 7 mol / L H2 S B 2 = 3 s : 2 4 . 10 - 6 mol / L 5 P2 : = 2 s : 4 . 6 . 10 - 6 mol / L e. B2 3( PO4)2 MM = 3 * 37 . 3 + 2 * 30 . 9 + 9 * 16 - 60 . 8 4 g / mol S B 2 3 (P O4)2 = 8 . 2 . 10 - 7 * 601 . 84 * 1 . 10 - 3 mg/L mol / g _ y (s) B2 3 (P O4)2 = 0 . 49 ppm 4 ( C . 9 ) a. Cl2 Fe ( CN6 ) I 2 \u21e3 2 ( Cl2 + ( Fe ( CN6 ) ) s 0 . 5 s b kB = [ Cl2 ] 2 [ Fe( CN6 ) ] C . 2 . 10 - 13 = ( 2 5 ) 2 5 3 . 2 . 10 - 15 B0 = 2 . 10 - 7 = 2 . 10 - 6 mol / L d S = 2 . 10 - 6 mol / L Cl2 ( Fe ( CN6 ) ) 3 cd = 2 5 : 9 . 10 - 6 mol / L S = S : 2 . 10 - 6 mol / L e. MM = 2 * 1 . 12 + 41 * 55 . 85 - 6 * 12 + 6 * 14 . 01 = 436 . 79 g / mol S = 2 . 10 - 6 mL * 436 . 79 g / mol * 1 . 10 - 3 mg = 0 . 87 mg L _ -1 S Fe (CN)7 = 4 . 9 7 ppm 5 . ( 3 C ) B2( OH)2 \u21e3 B a2 + 2 0 H - ( aq ) K Ps = [ B a2 + ] [ OH - ] 2 K Ps = 5 . ( 0 2 5 ) 2 K Ps = 5 . 4 5 2 K Ps = 4 . ( 0 1 0 ) 3 K Ps = 5 . 1 8 . 10 - 3 6 . 1 . 3 e . A g 3 - P Q 3 \u21e3 3 A g + + P O 4 - 2 K Ps = 9 ( 2 . 7 . 10 - 6 ) 2 K Ps = ( 3 ) 3 . ( 5 ) K Ps = 9 . 6 K Ps = 4 . 8 . 10 - 7