3º problema: resolva f(x) = x + ln x = 0 pode ser transforma...
3º problema: resolva f(x) = x + ln x = 0 pode ser transformado num problema equivalente da forma x = ψ(x). Para o processo iterativo definido por x_{k+1} = ψ(x_k): analisar a convergência quando:
![3º problema: resolva f(x) = x + ln x = 0 pode ser transformado num problema equivalente da forma x = ψ(x). Para o processo iterativo definido por x_{k+1} = ψ(x_k): analisar a convergência quando:
a) ψ(x) = -ln x,
b) ψ(x) = e^{-x},
no intervalo [0.5,0.6].](https://prod-meuguru-guruia-assets.s3.sa-east-1.amazonaws.com/MqIq1zQqsIT63sa-6yf3aJVTy?X-Amz-Algorithm=AWS4-HMAC-SHA256&X-Amz-Content-Sha256=UNSIGNED-PAYLOAD&X-Amz-Credential=ASIAQXTC4KK6RBSMTALJ%2F20250707%2Fsa-east-1%2Fs3%2Faws4_request&X-Amz-Date=20250707T082751Z&X-Amz-Expires=900&X-Amz-Security-Token=IQoJb3JpZ2luX2VjEGUaCXNhLWVhc3QtMSJHMEUCIBXUbR%2Bhq%2BJpoEGRSZ8338n0lYqv9leKDNx1bROHF9wCAiEAycsuhPYS1n%2FzS0H6QsRYNo1gM9kiaGcdrdhfPEo5udIq5QMIbhACGgwwNTA2NzMyNDI4MTMiDJ0b%2FZCvQLK4%2FOtqySrCAy2g9tH5gKhMjadz7AqrS7jIxtyuRTMIXsefIVHO5tO90iL39%2Fss0acKLfycRPqOxW6BB2ICiTLiuRrqZoXLw%2BbP1G553G9i9pN8suei%2FZGDiDUqfuWzSegb%2FcO4XIzhwPiisuhOCrD7YvBDKK1m6Rhafyzflv9LubAtR0mpdmqrumwx83eIObrIp0RJ%2FnU28QrtqQB1omurhcXm7pmWYBE5M967k56kzIB2gX%2FUC2SIXrbhV%2BXnGnwSxyhPivRpNMycblLU20MYyo%2Fiiz4P8qgORSQ7f7%2BDVTaZ9GCSw%2FOcO%2B01WrUUdmqd8T70ttC3CRyZsen4rci%2BO5oHBfWg%2BPjUWNVfRmWz6RuU6pw3TP%2BRLyGUVZ%2Bqqs4oacf9YSu6J1JLJNJDYZLMP%2FnEIiyrtOj46ooiPgUVUJLUyCU3UjSn8m9USqheW8I9%2B8fI0Xm00yc%2BCyOyWdwHEWnJRISW5N3sV92iDNyLvZipFdZg%2FhtUU2XwImtRxETQ9QfmvUpi58GHSEtNeFsneD9n7UPrwYsDLLFeuxnDb9mZJb2CHiiledW4z5cH5qN%2Fdz5CuQuDCD3hI8drgiolHyTJGBo7uSpzrjCJna3DBjqlAY0R9WJlB9z1ikcn5wXC0HVFuLP9wOGc3c47lXlxSfESVNNPffA52uQHzcWASszX2I%2FOqmLcpl8HSh8EO2j2siehjF2T9jrjek25oYTckYi9FDTGTfx6%2FFNy3zb7ITlN1wJtpv4Nkl6W7KGjxDEBenZB0P7R%2FWLT7T9J6iqqldsYZcjjj3yWGupz8mwHgUsaYyZrW%2BqL7wziW4slOeDsOHbgz9v1ZQ%3D%3D&X-Amz-Signature=a8fc29a01cda33d7a56c8f01b535fdd9c8aa0786399a7131592be868997ae935&X-Amz-SignedHeaders=host&x-id=GetObject)
