Download the Guru IA app
Android and iOS
Silvana
14 (EsPCEx/Aman-RJ) O valor da expressão E=(999)5+5⋅(999)4+10⋅(999)3+10⋅(999)2+5⋅(999)+1E= (999)^5 +5 \cdot (999)^4 +10 \cdot (999)^3 +10 \cdot (999)^2 +5 \cdot (999) +1E=(999)5+5⋅(999)4+10⋅(999)3+10⋅(999)2+5⋅(999)+1 é igual a
a) 9⋅10139 \cdot 10^{13}9⋅1013 b) 9⋅10159 \cdot 10^{15}9⋅1015 c) 101510^{15}1015 d) 999 999 e) 999⋅1015999 \cdot 10^{15}999⋅1015
15 (Mack-SP) Sabendo que ∑p=0n(np)=256\sum_{p=0}^{n} {n \choose p} = 256∑p=0n(pn)=256 então o valor de n vale: a) 8 b) 7 c) 6 d) 5 e) 4
Do you prefer an expert tutor to solve your activity?