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Estudos Gerais04/24/2025

3- F=1350kgf $A=?$ $P= 95 kgf/cm^2$ $A=\frac{1350}{95} = ...

3- F=1350kgf

A=?A=?

P=95kgf/cm2P= 95 kgf/cm^2

A=135095=A=14,21cm2A=\frac{1350}{95} = A=14,21 cm^2

d=2.Aπd=2.\sqrt{\frac{A}{\pi}}

d=2.14.213,14d=2.\sqrt{\frac{14.21}{3,14}}

d=2.4,52d=2.\sqrt{4,52}

d=2.2,127d=2.2,127 d=4,25cmd=4,25 cm ou

425mm//425 mm//

3- F=1350kgf

$A=?$

$P= 95 kgf/cm^2$

$A=\frac{1350}{95} = A=14,21 cm^2$

$d=2.\sqrt{\frac{A}{\pi}}$

$d=2.\sqrt{\frac{14.21}{3,14}}$

$d=2.\sqrt{4,52}$

$d=2.2,127$ $d=4,25 cm$ ou

$425 mm//$
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