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Emilly

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Estudos Gerais • 03/20/2025

37) -b + √(b² - 4ac) / 2a a = 20; b = 11; c = -3 -11 + √(11²...

  1. -b + √(b² - 4ac) / 2a a = 20; b = 11; c = -3 -11 + √(11² - 4 * 20 * (-3)) = 2, 20 -11 + √(121 + 240) = 40 -11 + √(361) = 40 -11 + 19 = 8:² = 4:⁴ - 1 5

esta certa? se sim me explique o pq se nao me explique o pq

37) -b + √(b² - 4ac) / 2a a = 20; b = 11; c = -3 -11 + √(11² - 4 * 20 * (-3)) = 2, 20 -11 + √(121 + 240) = 40 -11 + √(361) = 40 -11 + 19 = 8:² = 4:⁴ - 1 5
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