9. An object of mass 5 kg is moving at 6 m/s. A force acts on it for 0.1 seconds, changing
its velocity to 10 m/s in the same direction.
a) Calculate the initial momentum of the object.
b) Calculate the final momentum of the object.
c) Calculate the impulse delivered to the object.
d) Calculate the average impulsive force acting on the object.
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Accepted Answer

Okay, let's break down this physics problem step by step.

**a) Calculate the initial momentum of the object.**

The formula for momentum (p) is:

```
p = mv
```

where:
*   m = mass (in kg)
*   v = velocity (in m/s)

Given:
*   m = 5 kg
*   v (initial) = 6 m/s

So, the initial momentum is:

```
p_initial = 5 kg * 6 m/s = 30 kg m/s
```

**b) Calculate the final momentum of the object.**

Using the same formula, but with the final velocity:

*   m = 5 kg
*   v (final) = 10 m/s

So, the final momentum is:

```
p_final = 5 kg * 10 m/s = 50 kg m/s
```

**c) Calculate the impulse delivered to the object.**

Impulse (J) is the change in momentum:

```
J = Δp = p_final - p_initial
```

Therefore:

```
J = 50 kg m/s - 30 kg m/s = 20 kg m/s
```

**d) Calculate the average impulsive force acting on the object.**

Impulse is also related to force (F) and the time interval (Δt) over which the force acts:

```
J = F * Δt
```

We can rearrange this to solve for the average force:

```
F = J / Δt
```

Given:

*   J = 20 kg m/s
*   Δt = 0.1 s

Therefore:

```
F = 20 kg m/s / 0.1 s = 200 N
```

So, the average impulsive force acting on the object is 200 Newtons.

**Summary of Answers:**

*   **a) Initial momentum:** 30 kg m/s
*   **b) Final momentum:** 50 kg m/s
*   **c) Impulse:** 20 kg m/s
*   **d) Average impulsive force:** 200 N

9. An object of mass 5 kg is moving at 6 m/s. A force acts o...

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