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Estudos Gerais04/27/2025

A) $x²+ 7x+10=0$ $ \Delta=b²-4.0.6 $ $\Delta=(7)²-4.1.10$ $ ...

A) x2+7x+10=0x²+ 7x+10=0 Δ=b24.0.6\Delta=b²-4.0.6 Δ=(7)24.1.10\Delta=(7)²-4.1.10 \Delta=49+40 \Delta=49 X=\frac{-b± \sqrt{\Delta}}{2.a} X=-(-7)± \sqrt{9} X=\frac{+7±}{}B) B)x²-6x+9=0$

C)2x25x3=02x²-5x-3=0 A=b±(b24ac)/2 A=-b ± \sqrt{(b²-4ac)}/2 A=[5±((5)24.2.3) A=[5±\sqrt{((5)²-4.2.3)} A=(25+24)1 A=(25+24)1 A=49 A=49 X=b±4 X=\frac{-b± \sqrt{4}}{} X=b±(25+26)4 X=\frac{-b± \sqrt{(25+26)4}}{} X=[5+4914 X=\frac{[5+\sqrt{49}14}{} X=[5+77/4 X=\frac{[5+77/4}{} D)x27x+6=0x²-7x+6=0

A) $x²+ 7x+10=0$
$
\Delta=b²-4.0.6
$
$\Delta=(7)²-4.1.10$
$
$\Delta=49+40
$
$\Delta=49
$
$X=\frac{-b± \sqrt{\Delta}}{2.a}$
$
X=-(-7)± \sqrt{9}$
$
X=\frac{+7±}{}$
B)$x²-6x+9=0$

C)$2x²-5x-3=0$
$
A=-b ± \sqrt{(b²-4ac)}/2$
$
A=[5±\sqrt{((5)²-4.2.3)}$
$
A=(25+24)1$
$
A=49$
$
X=\frac{-b± \sqrt{4}}{}$
$
X=\frac{-b± \sqrt{(25+26)4}}{}$
$
X=\frac{[5+\sqrt{49}14}{}$
$
X=\frac{[5+77/4}{}$
D)$x²-7x+6=0$
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