cos 30° = \frac{BP}{50} \n BP = 50 cos 30° \n A distância ho...

cos 30° = \frac{BP}{50} \n BP = 50 cos 30° \n A distância horizontal BP = 43,3 m \n percorrida pelo barco e o vetor deslocamento são, respectivamente:

Um barco a vela impulsionada pelo vento descreve a trajetoria pelos vetores mostrados na figura. As distancias sao:

$cos 30° = \frac{BP}{50} \n BP = 50 cos 30° \n A distância horizontal BP = 43,3 m \n percorrida pelo barco e o vetor deslocamento são, respectivamente:$

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