Dada a função y=ln[a^{ln(tg x)}], onde 0<α<1. Então, y≥0 se:...

Dada a função y=ln[a^{ln(tg x)}], onde 0<α<1. Então, y≥0 se:

A) π/2<x<πe< x<2π B) 0<x≤π/2 e π<x<3π/2 C) 0<x≤π/4 e π<x≤5π/4 D) 0<x≤π/4 e π<x<3π/2 E) π/2<x≤π e 3π/2<x≤2π

$Dada a função y=ln[a^{ln(tg x)}], onde 0<α<1. Então, y≥0 se: A) π/2<x<πe< x<2π B) 0<x≤π/2 e π<x<3π/2 C) 0<x≤π/4 e π<x≤5π/4 D) 0<x≤π/4 e π<x<3π/2 E) π/2<x≤π e 3π/2<x≤2π$

Ask a question and receive an answer instantly

Ask Question

Ask your question

Send your questions through the App

Scan the QR Code and download for free

Do you prefer an expert tutor to solve your activity?

Receive your completed work by the deadline
Chat with the tutor.
7-day error guarantee