g(1) = -5
g(2) = 3
g(n) = g(n - 2) + g(n - 1)
g(3) =

Q: g(1) = -5 g(2) = 3 g(n) = g(n - 2) + g(n - 1) g(3) =

To find $ g(3) $, we use the recursive formula given: \[ g(n) = g(n-2) + g(n-1) \] We know: - $ g(1) = -5 $ - $ g(2) = 3 $ Now, calculate $ g(3) $: \[ g(3) = g(1) + g(2) = -5 + 3 = -2 \] So, $ g(3) = -2 $.

Question

g(1) = -5
 g(2) = 3
 g(n) = g(n - 2) + g(n - 1)
 g(3) =

Accepted Answer

To find $ g(3) $, we use the recursive formula given:

$$ g(n) = g(n-2) + g(n-1) $$

We know:
- $ g(1) = -5 $
- $ g(2) = 3 $

Now, calculate $ g(3) $:

$$ g(3) = g(1) + g(2) = -5 + 3 = -2 $$

So, $ g(3) = -2 $.