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Leticia

estudos gerais • 10/22/2024

h(x) = \begin{cases} 8 + 6x, & x < -7 \\ \frac{10}{x + 4}, &...

h(x) = \begin{cases} 8 + 6x, & x < -7 \ \frac{10}{x + 4}, & -7 \leq x < -5 \ 4x - 3, & x \geq -5 \end{cases} h(-5) =

h(x) = \begin{cases} 8 + 6x, & x < -7 \\ \frac{10}{x + 4}, & -7 \leq x < -5 \\ 4x - 3, & x \geq -5 \end{cases} h(-5) =
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