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∬R(6x2y3−5y4)dA,R={(x,y)∣0⩽x⩽3,0⩽y⩽1}\iint_{R}\left(6 x^{2} y^{3}-5 y^{4}\right) d A, \quad R=\{(x, y) \mid 0 \leqslant x \leqslant 3,0 \leqslant y \leqslant 1\}∬R(6x2y3−5y4)dA,R={(x,y)∣0⩽x⩽3,0⩽y⩽1}
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