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Estudos Gerais • 05/07/2025

$\left(\frac{12}{4}\right) \cdot \sqrt{4} + \left(\frac{6^2}...

(124)⋅4+(6222)=\left(\frac{12}{4}\right) \cdot \sqrt{4} + \left(\frac{6^2}{2^2}\right) =

$\left(\frac{12}{4}\right) \cdot \sqrt{4} + \left(\frac{6^2}{2^2}\right) = $
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