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Aluno
locercícitos 3x+23 x+23x+2 calcues al f(1)=f(1)=f(1)= log(2)=\log (2)=log(2)= cof(0)=\operatorname{cof}(0)=cof(0)= d. f(5)=f(5)=f(5)=
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