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Carlos
Nilton Exercício T=100 (10). Dada a funças F(x)=38x+123F(x) = 38x+123F(x)=38x+123, Caleule: a) f(-50)= le) f (12) = e) f(-16) = f) f(129) = c) f(-7) = g) f(-35) = d) f(68) = h) f(60) =
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