Sen(a-b) = Sen a cos b - Cos a Sen b Cos(45°-30°) = Cos 45° ...

Sen(a-b) = Sen a cos b - Cos a Sen b Cos(45°-30°) = Cos 45° Cos 30° + Sen 45° Sen 30° Cos(45°-30°) = \sqrt{2}/2 \cdot \sqrt{3}/2 + \sqrt{2}/2 \cdot 1 = \frac{\sqrt{6} + \sqrt{2}}{4}

h = \frac{j}{j+h} \frac{h}{j+h} = \frac{h}{4} = \frac{\sqrt{6}-\sqrt{2}}{4}

Está correto?

$Sen(a-b) = Sen a cos b - Cos a Sen b Cos(45°-30°) = Cos 45° Cos 30° + Sen 45° Sen 30° Cos(45°-30°) = \sqrt{2}/2 \cdot \sqrt{3}/2 + \sqrt{2}/2 \cdot 1 = \frac{\sqrt{6} + \sqrt{2}}{4} h = \frac{j}{j+h} \frac{h}{j+h} = \frac{h}{4} = \frac{\sqrt{6}-\sqrt{2}}{4}$

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