$\sqrt{3}$ + $\sqrt{50}$ -$\sqrt{9}$ + $\sqrt{25}$ +3$\sqrt{40}$

Question

Accepted Answer

Okay, I will evaluate the expression.

The expression is:
$$
\sqrt[3]{3} + \sqrt{50} - \sqrt[3]{9} + \sqrt{25} + 3\sqrt{40}
$$

Let's simplify each term:
1. $\sqrt[3]{3}$ remains as it is.
2. $\sqrt{50} = \sqrt{25 	imes 2} = \sqrt{25} 	imes \sqrt{2} = 5\sqrt{2}$
3. $\sqrt[3]{9}$ remains as it is.
4. $\sqrt{25} = 5$
5. $3\sqrt{40} = 3\sqrt{4 	imes 10} = 3 	imes 2\sqrt{10} = 6\sqrt{10}$

So the expression becomes:
$$
\sqrt[3]{3} + 5\sqrt{2} - \sqrt[3]{9} + 5 + 6\sqrt{10}
$$

Rearranging the terms:
$$
\sqrt[3]{3} - \sqrt[3]{9} + 5\sqrt{2} + 6\sqrt{10} + 5
$$

Since none of the terms can be combined further, the simplified expression is:
$$
\sqrt[3]{3} - \sqrt[3]{9} + 5\sqrt{2} + 6\sqrt{10} + 5
$$

Thus, the final answer is:
$$
5 + 5\sqrt{2} + 6\sqrt{10} + \sqrt[3]{3} - \sqrt[3]{9}
$$

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$\sqrt{3}$ + $\sqrt{50}$ - $\sqrt{9}$ + $\sqrt{25}$ +3 $\sqrt{40}$