$ (x+7) \cdot(x-7)= $

Q: $ (x+7) \cdot(x-7)= $

To simplify the expression $ (x+7) \cdot(x-7) $, we can use the difference of squares formula, which is $ a^2 - b^2 = (a+b)(a-b) $. Here, $ a = x $ and $ b = 7 $, so we have: \[ (x+7) \cdot(x-7) = x^2 - 7^2 \] Simplifying further: \[ x^2 - 49 \] Therefore, $ (x+7) \cdot(x-7) = x^2 - 49 $.

Question

Accepted Answer

To simplify the expression $ (x+7) \cdot(x-7) $, we can use the difference of squares formula, which is $ a^2 - b^2 = (a+b)(a-b) $.

Here, $ a = x $ and $ b = 7 $, so we have:

$$
(x+7) \cdot(x-7) = x^2 - 7^2
$$

Simplifying further:

$$
x^2 - 49
$$

Therefore, $ (x+7) \cdot(x-7) = x^2 - 49 $.

\( (x+7) \cdot(x-7)= \)