⎧
x + y = 25
⎨
3x - y = 35
⎩

Q: ⎧ x + y = 25 ⎨ 3x - y = 35 ⎩

To solve the system of equations: \[ \begin{cases} x + y = 25 \\ 3x - y = 35 \end{cases} \] You can use the method of elimination or substitution. Here, I'll use elimination: 1. Add the two equations to eliminate $y$: \[ (x + y) + (3x - y) = 25 + 35 \] This simplifies to: \[ 4x = 60 \] 2. Solve for $x$: \[ x = \frac{60}{4} = 15 \] 3. Substitute $x = 15$ back into the first equation to find $y$: \[ 15 + y = 25 \] \[ y = 25 - 15 = 10 \] So, the solution is $x = 15$ and $y = 10$.

Question

⎧
 x + y = 25
⎨
 3x - y = 35
⎩

Accepted Answer

To solve the system of equations:

$$
\begin{cases} 
x + y = 25 \
3x - y = 35 
\end{cases}
$$

You can use the method of elimination or substitution. Here, I'll use elimination:

1. Add the two equations to eliminate $y$:

$$
(x + y) + (3x - y) = 25 + 35
$$

This simplifies to:

$$
4x = 60
$$

2. Solve for $x$:

$$
x = \frac{60}{4} = 15
$$

3. Substitute $x = 15$ back into the first equation to find $y$:

$$
15 + y = 25
$$

$$
y = 25 - 15 = 10
$$

So, the solution is $x = 15$ and $y = 10$.

⎧ x + y = 25 ⎨ 3x - y = 35 ⎩

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