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GUILHERME
33 Resolva as seguintes equações: a) (n + 2)! = 6 . n! m=1 e b) n! = 120 m=5 m=5 c) n! / (n - 2)! = 42 m=7 d) (n + 2)! - (n + 1)! / n(n - 1)! = 25 e) (n - 5)! = 1 m=5 ou f) (n!)^2 - 100 . n! = 2400
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