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Engenharia Mecânica ·

Termodinâmica 1

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Exercício ηc = 80% ηb = 80% P4 = 3,0 MPa T4 = 420ºC P5 = 4,5 MPa T5 = 400ºC P6 = 5 MPa T6 = 500ºC vapor d´água a 380ºC e 3 MPa hi = 3115,25 kJ/kg si = 6,7947 kj/kgK s1 = 0,64975 siv = 5009 Kj/kg 285 = 6,7947 - 0,64975 / 7,5009 = 0,8125 h0,5 = h1 + x . hv het = 891,4 + 0,8125 . 2532,8 = 3103,92 Kj/kg hb = 2155,92 Kj/kg wB = 2155,92 - 2155,92 e o ηe = (1080 - 2155,97) Ve = 842,61 ηb = h2s - ht / h2s - ht = 2155,92 Kj/kg wb = vt(p1 - p2) wb = vt(p1 - p2) ηb wb = vt(p1 - p2) = 0,001009 . (5000 - 10) /0,80 63 Kj/kg wb = 63 Kj/kg 9H = h4 - h3 = 32136 - 171.8 = 3041,8 9H = 3041,8 kJ/kg η = wliq / 9H = 842,61 - 63 / 3041,8 = 0,2749 η = 27,49%