Prova1-hidraulicai

Prova 1 - Hidráulica I - Turma 21 e 22\nm = 150 kg\nD: 100 cm x R: 5 cm \u2192 7,85 \u00b7 10^{-3} m²\n\u03b3e = 22555,29 N/m³\n\u03b3h2 = 133370,44 N/m³\n\u03b3c = 820 N/m³\nPatm = 101300 Pa\nPB = A mg + Patm A \u2192 PB = Patm + m g/A\nPB = 101300 Pa + 15,9 \u00b7 81/7,85 \u00b7 10^{-3} = 116,3 kPa\nPB = 116,3 kPa\n\u03b31 = \u03b3e\n\u03b32 = \u03b3e + \u03b3c g h1\n\u03b33 = \u03b3e + \u03b3c g h2 - \u03b3c h3\nPC = PB + \u03b3 (PB h1 + \u03b3 h2 - PC h3)\nPC = 116,3 (22555,29 \u00b7 0,25 + 133370,44 \u00b7 0,15 - 820 \u00b7 0,2)\nPC = 116,3 kPa + 25,48 \u2192 PC = 141,78 kPa ou 19,458 mca// Sistema de equilíbrio\n\u2211Ma = 0\n\u2211Ma = FadaA - FdlAl - PalA - f dAf\n\u2211Ma = FadaA - FdlAl = 2)\nFa = \u03b3A\nh = 1,5 \u00a7 2 = 0,75\nFa = 1,0,75 \u00b7 4,2427 = 3,1820\ndA =\nygA = ygA = 1,607 \u00b7 1,5910 = 1,4147\n1,007 \u00b7 1,2427\nyg = 0,75 \u00b7 0,75 = 1,607\nIg = bh²/12 =\nIg = 1,5910\nFL = \u03b3A\nh = hcd = 1,5 \u00b7 0,75 - 0,75 \u00b7 1,75 m\ndA = 1,2427\nf = 1,5 \u00b7 1,75 \u00b7 1,2427 = 11,2427\ndl =\nyL - yg + Ig\nyg = hg \u00b7 0,75 \u00b7 0,7071\nyg = 2,4799 + 1,5910\nyl = 2,4799 + 1,5910\n\nI = A = 1,2427\nIg = bh²/12 P = 25t \ndA = b/2 \u00b7 cos 45 = 1,1213\ndaf = 6\nSubstituindo na equação I\nf = 3,1820 \u00b7 2,8285 + 11,2427 \u00b7 1,6162 + 2,5 \u00b7 2,113\nf = 5,4123 129.9 m - 7m\n750m\nR1\nR2\nD: 0.00\n\nLocais: D: 0.15m | f: 0.026 | P1: 38 mmca | P: 93.61 kw\nQ: | L: 750m\n\nΔH: ρ * g * V²\nD 2g\n\njH: H3 = H2 + ΔH3\nΔH: H3:\n= 0.75 - 0.026 750 m²\n= -75.196 = 130. m²\n= 147 = v²\n130\nT: T = √ 130B - V2 = 1.063\n\nQ = 0.01680 m³/s -> 186.8 l P1: 10mca = 32640 Pa\nA: A = πd²/4 = π(0.15)² * 0.017362 m²\nV = Q/A = 0.004 m³/s\nP2: 9260 Pa\n\nEq. de energia:\nV1 + P1 + Z1 - P2 + V2 - Z2 = 0\nhPmax = V² - (P1 + P2) + (Z2 - Z1)\n2gD\n= -1.064 * ( (9260 - 12640) + 75 - 129 )\n2.98 9500\n= 219.27m\n\nhPmax : fl * V² = hPmax * 2D : 16\n2gD fn²\nL = 219.27 * 2.96 * 0.15 / 0.026 * 1.064²\n= 249.963 m Q: 0.003 m³/s\nf: 0.026\nD: 0.15m\nL: 750m\nTi: 7\nZ2: 2\nL2: 50 m\nA: 0.017361 m²\nV = Q/A\n\ndpP2 = 0.003 750 0.02676² 19.119m\n2.98 0.15\n\nEq. de energia:\nV2: P2 + Z2 - L P2 + h0 V² - h2 P2 - Z2\n2gD\nH3: (Z2 - Z2) + hP2 P3\n= 75 + 19.119 = 26.619\n\nP0: Q * h2 = 11179.946W -> P0: 152 CV ④ a) h_f = 75 - 55 = 20m\nve = \\frac{Q^2}{g \\cdot L} \\rightarrow Q^2 = \\frac{L \\cdot ve \\cdot g}{h_f} \\rightarrow L = \\frac{\\pi^2 \\cdot 9.81 \\cdot 0.2^5}{8.903 \\cdot 12.00} = 8.903 \\cdot 12.00 = > Q = 0.335 m^3/s \\\\ Q = 33.5 l/s\n\nb) Q = 45 l/s = 0.045 m^3/s\nQ = vA \\rightarrow v = \\frac{Q}{A} \\rightarrow 0.045 = \\frac{1}{0.034} = 1.4331\\\nU = \\frac{\\pi \cdot 0.2^2}{4} = 0.00314\n75 + h_b = 55 + \\frac{0.003 \\cdot 2.3 \\cdot 10^{-3}}{0.2} \\rightarrow \\frac{(4 \\cdot 0.045)^2}{\\pi \\cdot 0.2^2 \\cdot 2.98} = 16.14\nh_b = -20 + \\frac{0.003 \\cdot 2.3 \\cdot 10^{-3} \\cdot 0.045}{0.2^2 \\cdot 0.2^2 \\cdot 2.98} = 16.14\nPot = 9.8 \\cdot 16.11 \\cdot 0.045 - 9.4727 KJ au 12.88 Cv/0.75\n\nc) \\Delta h_f, f = \\frac{0.03 \\cdot 383.33 \\cdot 1.433^2}{D \\cdot \\frac{V^2}{g}} = \\frac{L}{2.98 .0.2} = 6.02\nz_a = P_l + z_0 + \\Delta h_f \\rightarrow 75 = P_{abs} + 65 + 6.02 \\rightarrow P_{abs} = 3.98 mH_2O\\\\\nP_{depos} = \\frac{75 + 16.11 - 65 - 6.02}{8} = P_{depos} = 20.09 mH_2O\\