Prova Fisica1

Nome: Samuel França de Araujo 1. v=90 km/h = 90/3.6 = 25 m/s S=75 m S=So+Vot+at^2 S=vt=>2s,0,s V^2 = V0^2 + 2 a . \Delta S 0,25s^2+10 \Delta S DS=62S => \Delta S=62,5m 2.a- t=60s a=\Delta V = V - Vo => 6-0 = \frac{0,1 m/s^2}{t - to} V= 6 m/s B-SA=SB 0,1t^2 + 4t t^2 = 80t t^2 - 80t = 0 t = 80s => instante 3. a- Ts=V0 => 5 m/s => Ts=0,5 s s= 0,5 + ((-10) 0,5^2 => 2,5 - 1,25 S=1,25m+10,0m \beta-S=So+Vot+at 2=2^2,25 tj=1,5 \text{TP}=Ts+tj => TP =0,5 + 1,5 = 2,5 \, s