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Engenharia Elétrica ·

Resistência dos Materiais 1

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V at h = N\n\nz0 -\n(9.4897 - 0.005) = N\n\nz1 -\n(1.8099 - 0.006) = N\n\nh2 =\n√(809) = 95.9 = N\n\n\n 0 = N + 0.0000 (V at 0) \n (510) x 0.005 = N + z1 - N = 0 \n z1 = N + 0.0000 \n\n0 = 0.009 * N + 0.0000 - N \n0.000 = 0.0000 - 0.0000 + N + 0 \n\n0 = 4 + + N\n\n0 = 0.0000 - 0.009 * N + 0.0000\n\n\n V at z0 \n \n (z 0 - (9.5*(N - N)))\n (8.00) = (A - 9.5) div 0.5 = \n / 950 \n = (S.0)\n