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Engenharia Eletrônica ·

Engenharia Econômica

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Resposta:\nJ = 5000,00(0,12)3 = 1.800,00\nM = 5.000 + 1.800 = 6.800,00 Resposta:\nM = 6.000(1 + 0,02)7 = 6.000(1,02)7 = 6.367,25\nj = 6.367,25 - 6.000,00 = 367,25 Resposta:\nM = C * (1 + i)²\nM = 5000(1 + 0,18)2\nM = R$ 5.962,00 Resposta:\nC = Pn * [(1 + i)^n - 1] / [i * (1 + i)^n]\nC = 1230,0 * [(1 + 0.019)^48 - 1] / [(1 + 0.019)^48 * 0,019]\nC = 1230,0 * [(1.019)^48 - 1] / [0.019]\nC = R$ 37.804,82 Resposta:\nD = M * d * i\n24% ao ano / 12 meses = 2% a.m\nD = 12.300,0 * 0,02 * 6\nD = R$ 1.476,00 Resposta:\nI = (1 + i)^n - 1\nI = (1 + 0,1)^11 - 1\nI = 1,2682 - 1 = 0,2682 ou 26,82% Resposta:\nJ = 5000,00(1,12)³ = 1.800,00\nM = 5.000,00 + 1.800,00 = 6.800,00 Resposta:\nM = 6.000,00(1 + 0,02)² = 6.000,00(1,02)² = 6.367,25\nJ = 6.367,25 - 6.000,00 = 367,25 Resposta:\nM = C(1 + i)ⁿ\nM = 5.000,00(1 + 0,18)ⁿ\nM = R$ 6.962,00\n\nResposta:\nM = C(1 + i)ⁿ\nM = 5.000,00(1 + 0,09)ⁿ\nM = R$ 7.057,91\n\nResposta:\nPₙ = M × (1 + i)ⁿ = (1 + i/n)ⁿ × (1+(1 + i)ⁿ)\n1199 = (1 + 0.023456)ⁿ × (1 + 0.023456)ⁿ × (1 + 0.023456)ⁿ\n1199 = 1.023456ⁿ × 1.065956539 × 1.00562257\n1199 = 3.41008956 × M\nM = 425,89 Resposta:\nC = P_0 (1+i)^n - 1\n (1+i)^n - 1\nC = 1230, \nC = 1230_ \n(1+0.019)^8 - 1\n(1+0.019)^8 - 0.019\nC = 1230_ \n(1.019)^8 - 0.019\nC = R$ 37.804,82 Resposta:\nD= 10000_ \n[1 - (1 - 0.018)^2]\nD= 10000_ \n[1 - (0.982)^2]\nD= 10000_ 0.156849\nD= R$ 1.968,49