Avaliação Discursiva Questao 2 - Resistencia

Diâmetro externo AB= 18.75 mm= 0.01875 m Diâmetro interno AB = 17 mm= 0.017 m 𝜎A: A/P=(M/Z)+I/(A*e^2) AB~9/[(17/30)*e^9]+ AB~9/(17*9)/[(17/30)*e^8] T1=9-4*9 T1=9-9/9 T1=17.5m T1=12x9 11.25=15x 9/30*9 9e^9 T3= ABP= 3TixA/BP+9M/P* A3MN/PZ9T3/17.5P/10^9 T4= A/Pmpar: broj BC. TI/AE=(Ms/NPe) T3MpPbN/[(e)^10T3 Diâmetro externo BC= 25 mm= 0.025 m Diâmetro interno BC = 21.5 mm= 0.021 m 𝜎C: BC=P/ BC-4/[(3C-4)-9C] BC=29/9[10^2.5 *9(10^5*x^4)] BC=17[9*(1,7*8)=4 C=10/37 T2=5 N/m