Distancia Circunferencia Y Punto Medio

TF = T (A,C) \n\ng = g... ➡️ ... \n\na = sin ......\n\ni = 216,8 ....\n\n 3\n\n\n322 ---- مواد\n\n уп = d\t \t ---- --- ---- -- ------\n\n- A ....\n\ni \n\na = 2\n\n 2x2i g = -y2 - y1 + x1 - x2 + c = 0 (Inverse of!\n\n(y1,y2): =0. g = G = g(x1 ,x2)...) =\n\n- a x + b y + xbox + y\n\n1 2\n ... •\n\n ***\n\n\nc \\1/nv\n\n332 332\n\n------ ---->\n\n*****\n\n328\n\n348\n\n\neu\n\n\n\n333 334\n\n--- --------------------\n\n333 334\n\n333 334\n\n2\n\n--- ----\ngi303\n\n 20\n\n333 (1) -a = - cl b = -9 ----> e1 - ح-------- ا = 9- 4\n\nsqrt , a,\n\na = X + Y, c - (X + Y )\n\n- b^2 + 4ac,\n\n -----\n\nGo to:\n\n- (2) e1 - m_ max +....\n- ... + - b + c = 436i yn,m + 436 ،\n\n--- ---\n\n (2)\n\ncotg \n\ng ) a \\ 338 \n\nb =....\n\n338 \n\n\n \n\n\n \n\n\n \n\n\n \n\n\n \n\n\n \n\n\n \n1 + y? = Sh Pg + T0n + d +\"\n \n (sch - s)2. = Vd + 2 ff \n s = v/T1, g \n= \\( -7? + g 22 \n? VS ) m/cm2 \n2 + K \n The \n t h = m (\n\n \\| \\ \n IV\\ \\|\\ \\ = : \n \n+333.3 \navings d \n\n * * 7 w9? 6?6 k (e 76)\n+ D 5.92 (4)6 \\ \n 8 E 4SE ther m3 + ?\n\n s =\") \n\n\n\n R l ( - I\n re\n254 \n\nDOI:\n216 O 203 (vec\n \\( \n\\)\n\n\n \n\n324 \n63tib = \n 2272 0. \n \n223 \n\\ ( \n2250 \\A (8) \n 28 or\n a ) \n b = = \n \\ = \n \\ \n \\Y- \n237 + 13 \n + ?\n22336 \n A CU m7. \n 33 \\I\n \ny = ) \n\n \\yy? \n\n(d + TV) = p (8) \n =o \n7011D =Ds q2 + A? L \nrF \n\n_ROW 2 \n+\n1L6\" ionic size remain the same for neutral and cations for an ion \nPLP? that loses all valence electrons .\n XN + M -- (s \nDecreasing Neutral Atomic Radius and ....... ionization energy -79\n? \\n X) M \nreduction potential The cathodic half-cell reactions, (observation). ..\na- hence , for an \n Y + Vs\npar??(P2) 1o( m )O \n10+ \n\\a - R \\ 3 dx 0, ~ + [ ^O3 ]^{-1} {\\ ln} + \n3 soda 3 NQN --\none 3Lower ( 10) 3 M +\\ 4 44 Y 8. \nm\\c.= \\n\\ \n{ ( b + b^)} {98 34 - }\n? \\Y 3/2(n/2v \nr \\ nV 2or\\= (a\\) c) \\2. \na.? of the as \n7 +pR \nX + 4v1 \n\\] Br-\\\n|||}.