1av Resistência dos Materiais Aplicada

Nome: Sistema Truss de Símbolos\nMat.: 01213560\n\nAnálise de Resistência dos Material\n\n1) Reação de apoio:\nΣM_A = 0: 1.5 * 36 - 2.25 * R_B + 4.5 * 0\n2R_B = 13.62 kN\n\nΣF_y = 0: R_A - 12 + 36\nR_A = 35.33 kN\n\n2) Deslocamentos:\nV_O = 13 kN\nV_A = -13 + 35.33 = 22.34 kN\nV_B = 22.33 - 36 = 23.67 kN\n\nA_1 = -13.5 - 19.5, cm/mm\n22.33 - (-13.67) = 22.33 * x = 2.19 m\nx = 2.19 m\n\nA_2 = -19.5 + 22.33 * 2.20 / 2 = 11.65 km\nA_3 = 11.65 - 13.67(4.5 - 2.90) / 2 = 0 1) Valores de Geometria:\n\n\tn_y (mm)\tA (mm²)\tt_o (mm)\tI (mm⁴)\n1\t25\t\t750\t\t183.60\t\t156.250\n2\t125\t\t500\t\t939.50\t\t160.6250\n3\t2\t\t1500\t\t11.500\n\nY_k = ΣY_A / ΣA = 75 mm\n\n2) Tensão máxima:\n\nTração = 6 * 19.5 (200 - 75) * 10⁻⁵\n\n\sigma = 68 / 19.5 = 45.0 MPa\n\n3) Estrutura:\n\tx_0 = 1 m / m_m\n\nΣM = I + I_2 + 2AI (y̅ - y_cg)² + A_2 (y̅ - y_am)²\n= 64720 + 2.2400 (20 - 17.67)² + 240 (13 - 17.67)²\nI(m) = 72560 mm⁴ 1) E1 = C1\n\tn_y = 0\n\nM = 0\n\n\tdx: P_x L - L\n\nt_0 = -M/I\n\ntau = P_i * I\n\n2) E2:\n\nx_1 = 0; A_1 = A_2 + A_3\nV_2(x) = 0.02 (x = 1/2)\nV(x) = (7.3) / (3) + 8*R/48\n\nV_max = V_1(x=1) + V_2(x=1)\nV_max = 1/2* I + x = 1 + Q \n= -t / 6 comp a/ti\n7 ak = 74.62\nL2 = \\( \\pi 0^4 / 64 \\) = 7.85 \\times 10^{-9} m^4\n\\( d10^{-10} = \\pi \\cdot 210 \\cdot 105 \\cdot 7.85 \\times 10^{-10} = 16.2760 \\) \nL2 = 385 mm\n\n1) a) 60 = 89 kV => L1 = 362736 \\( 89.10 \\)\nL1 = 40.5 cm\nb) 10 = Rn = 11 kV => L2 = 162740 \\( 14.10 \\)\nL2 = 148 m