57 Deformação Lateral - Coeficiente de Poesson

E = 200 g.m.\na = \u03B1 A + \u03B1 l \u221210\u00b0C\nE2 = 10.1 GPa\n\u03B1z = 18 x 10\u22126 /C\nR1 = R2\n200 x 10\u2079 10.1 x 10\u2079\nDeformacao Lateral - Coeficiente de Poisson\nSeja uma barra prismatica sob acao de uma carga social P de tracao\nP1\nP2\n\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\nL = l + \u0394l\nE1 = E\nEc = \u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\nEl = deformacao especifica longitudinal\nl\n\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\u2014\nSa = Et - deformacao especifica transversal\nEt = \u2212\nE = (0.23 x 103)\nVariação do volume de uma barra tracionada\nSeja novamente a barra (1)\n\nR1 = lP / l \u2192 l\na + \u0394l / l = (1 + \u03B5l) = l (1 + El)\n\n\r\n\n\n\n\nP1 a = a(1 + \u03B5a) = a(1 + ct) = a(1 + ct)\n