Exercicio Hidraulica

K_s = \\frac{1 - (\\sin 26.6)^2}{\\sin 87} \\Rightarrow K = 0.56.\n\nJ = 0.75 \\cdot 1.5 = 1.3 Pa = Ucef \n\nJ = 0.25 \\cdot 15 \\cdot 0.56 = Octano = 0.63 Pa.\n\n\\text{Exercício 1}\nO \\text{s} é a área molhada de um trico de 41° e 5cm², qual é o perímetro molhado \nD = 4 \\cdot 0.0254 = 0.102 m \\Rightarrow D = 10 cm\nA = (\\theta - \\sin \\theta)\n6 \\text{,}\nA = \\frac{D \\cdot D \\cdot 0.5}{8}\n0.4 = (\\alpha - \\sin \\alpha)\n\\begin{array}{|c|c|}\n\\hline\n\\theta & \\theta - \\sin \\theta \\\n\\hline\n0.9 & 0.12 \\\n1.3 & 0.37 \\\n1.39 & 0.40 \\\n\\hline\n\\end{array}\nP_s = \\frac{\\theta \\cdot D}{2} \\Rightarrow P = \\frac{1.39 \\cdot 10}{2} \\Rightarrow P = 9.95 gm.