Exercício Resultante de Forças 2d - Beer Johnston 11ed Cap2 Ex2 35

2.35 Sabendo que \\u003d 35\\u00b0, determina a resultante das tr\\u00eas for\\u00e7as indicadas.\n\n 20 N\n \n 100 N\n\n 150 N\n\nF_{Rx} + F_{Fx} + F_{Sx} = - 15,52 N\nF_{Ry} + F_{Fy} - F_{Sy} = - 306,08 N\nF_{R} = \\u221a (F_{Rx} + F_{Ry})\nF_{R} = 308,58 N\n\nF_{Fx} = F_{F} \\times cos (\\u03b8) = 500 \\times cos 35\\u00b0 = 163,66 N\nF_{Fy} = F_{F} \\times sin (\\u03b8) = 500 \\times sin 35\\u00b0 = 421,67 N\nF_{Sx} = 100 \\times cos(30\\u00b0) = 84,87 N\nF_{Sy} = 100 \\times sin(30\\u00b0) = 50,00 N\nF_{Tx} = 150 \\times cos(60\\u00b0) = 75,00 N\nF_{Ty} = 150 \\times sin(60\\u00b0) = 129,90 N\n\nF_{R} = \\u221a[( - 15,52)^2 + (- 306,08)^2] = 308,58 N\n\\n\\n\\n\\ntan \\u03b2 = \\u221a(\\frac{|F_{R}|}{|F_{T}|})\n\\u03b2 = 86,50\\u00b0\n