Exercício Resultante de Forças 2d - Beer Johnston 11ed Cap2 Ex2 41

2.41 Determine (a) the tension necessary in cable AC, knowing that the resultant of the three forces acting at point C must lie along line BC, and (b) the corresponding intensity of the resultant.\n\nFigure P2.41\n\nF_{T} = 45 \, \text{N} \, \sin(65^{\circ}) = T\nF_{T} = 45 \, \text{N} \, \cos(65^{\circ}) = 0.518 \, R\nR = R_{x} + R_{y}\nR_{x} = T \, \cos(65^{\circ}) + 0.518 R\nR_{y} = T \, \sin(65^{\circ}) - 50 \, \text{N} \n\n\n em: resulta: F_{y} = T_{y} = 0\n em: F_{x} = 0 \, \text{N}\n\nT = 0.524 R\n314.10 - 0.506(2.7172 - 1.936R) - 0.54R\n314.10 - 257.61 + 1.154R - 0.54R\n+ 220.91 = 2.12838 R\nR = 94.85 \, \text{N}