Hidráulica

1. Q_a = 37 + 2x = 35.204 L/s\n Q_b = 30.51x = 50.51 L/s\nQ_a = 0.035 m/s\nQ_b = 0.050 m/s\n\nL_s = 300 m\nD_i = 0.225 m\nf_1 = 0.020\nL_2 = 150 m\nD_2 = 0.125 m\nf_2 = 0.028\n\nL_3 = 250 m\nD_3 = 0.180 m\nf_3 = 0.022\n\nL_4 = 100 m\nD_4 = 0.175 m\nf_4 = 0.030\n\n\nTecho 1:\n∆H_1 = 0.0827 * f_1 * Q_1^2 / D^5\n∆H_1 = 0.0827 * 0.030 * 0.035^2 / 0.2275\n∆H_1 = 6.22 m\n\nTecho 2:\n∆H_2 = 0.0827 * f_2 * Q_2^2 / D^5\n∆H_2 = 0.0827 * 0.024 * 0.02^2 / 0.125\n∆H_2 = 4.6134 m\n\nTecho 3:\n∆H_3 = 0.0827 * f_3 * Q_3^2 / D^5\n∆H_3 = 0.0827 * 0.022 * Q_3^2 / 250\n\n∆H_3 = 5.98978 * Q_3^2\n\nQ_2 + Q_3 = 0.05\n1 * 381.64 * Q_2^2 - 5.98978 * Q_3^2\nQ_3 = -1.38 Q_2\n\nQ_2 + 1.38 Q_2 = 0.05\nQ_2 = 0.021 m/s\nQ_3 = 0.029 m/s\n\n∆H_2 = 14 * 381.64 * Q_2^2\n∆H_2 = 1 * 381.64 * (0.00121)\n\n∆H_2 = 5 m ∆H_4 = 0.0827 * 0.050 * (0.005)^2 * 100\n\n10.175\n\n1∆H_4 = 3.18 m\n\na1 ∆H_T = 6.22 m + 5 m + 3.78\n∆H_T = 15 m\n\nb1 P_y\n\nZ_2 = C_P2 + ∆H_2\nC_P2 = Z_2 - ∆H_2\nC_P2 = 15° - 6.22\nC_P2 = 8.78 m Thalisson Seten Canto Silva\n\n21.010 + 200 → x = 0.10200\n\n2. ∆H_4 = 812.00 + 50 x = 812.1 m\nH_0 = 800.00 + 100 x = 805.1 m\n\nH_A = 817.1 m\nH_B = 805.1 m\n\n∆Z = (817.1 - 805.11)\n∆Z = 12 m\n\nD = 6.0 / 0.524 m\nD = 0.152 m\nL = 10.25 m\nf = 0.025\n\nH_9 = 7 - 0.32 * 86\n\nH_n = -12 m + 2.37594 * Q^2\nH_n = -12 m - 3.685\n\nH = 10.22 m\n\nQ (m/s) 0.006 0.018 0.024 0.03 0.036\nH (m) 22.6 21.9 19.7 19.2 17.5\n0 7 0 32 86\n\nH_9 = -7.9\n\nH = 10.22 + 10.22 + 5.98979 -> Nova Vz 2\n\nQ_3 = 0.029 m³/s\n0.029 - 0.03 = η = 7.66\n0.024 - 0.03 = 95.66\n\nη = 69.1%\n\nPe = 10.22 - 9.81 - 0.029\n0.69\n\nPe = 4.21 Kw\n\nC_P = Ζ + H\nC_P = 817.1 + 10.22 = \nC_P = 821.32 m Qd = 0,006 L/s\nPdm = 0,47124 m\nL = 839,1 m\nPdc = 0,15724 m\nL = 400 m\nZá = Cpb + 10,65 - Qab * L\nCpb = Cpa + 4,932.85 - Qab\nCpb = Z0 - 9,5 + 4,932.85 (Qm - 0,0034204)¹,85 Qm = 0,0268 m³/s\nQc = 9 L/s + (10,0268.10⁻³ = 3,4204)\nQc: 97,23,38\nQc: 32,38 L/s