Prova Np2 Teoria

Questao 1 \nSistema Principal \nCaro 0 \n20kN \nVz= 1 \nV2 \n- 2(x)=0 \nV2 x 12 - 20 x 12 x 6 - 80 x 3 = 0 \nV2 = 140kN \nV1= 180kN \nH1= 180 x 0,8 = 144kN \nv1=180 x 0,6= 108kN \nsinalfa=0.8 \ncosalfa=0.6 \nD.M.F \nM3,5=BA x para z=5 \nM5,5= \nM4 = 540 - 9.90 = 450kNm \nM5 = 420 -90 = 330 x 90 \n420kNm \nM2 = B2.2 \nM1 = 108 x porta,=0 \nM4= 450-40x-10x2\n Caro 1 \n4,1 \n1x senalfa=0,8 \nHi=1x \ncase=0,6 \nH=1 kN \nV= 1x senalfa =0.8 \nH1 = 1- \nRico \n4kN.mm \nx=1 \nM4=0,8x5=-4kN.mm \nM5,5=-9,8x5=-4kN.mm\nCalculo des tapores \nT10=5x(4)x5,0 + 5x(-4)x420+( \n3x JE \n3xJE \n+ \nT10 = -6400 + T \nT10 - 10000 JE \n3JE \nJE\n \nS11=(-4) (A)5x2+(-4)(A)6\nS11=58.33 \nResolva sistemn \n100 \n12=5 \nEJ \nJJ \n+117.19 \nMA,5 - M5 \n117.19 \n= \nMA = 540. 4x117.19=k1.3 kN \nM2,5= 420 \nMa1= \nMa5= -18,5 x 4x11719= \n5 -420. \nim 4x-18.5 x \nJA2 = \nvoirtual = 119 x cm =150kN \nVaz=40cm \nMumun \n21.5kN.mm \nVan D.E.N (KN)\n-141.3\n-167.1\n-182.3\n\nD.E.C (KN)\n-200\n60\n40\n-80\n94\n143\n90\n\nD.M.F (KN.m)\n90\n130.5\n111.3\n245\n128.7\n130\n94 Questao 2\n30KN\n20KN/m\n4\n6\n3\n3\n40\nSistema Principal\n-60\n-60\nCaso 0\n30KN\n20KN/m\nBarra1/B\nHi\nMi = Mz = 20x6^2 / 12 = 60KN.m\nM2\n-60\n-60\nMi\nMi\n-60\nM2\n-150\nB0 = -150\nB20 = 150 Caso 1\nY load\nBarra 1,A\nY load\nMu = 4EJ / 5 = 0.8EJ\nMi = Mx1 = 2EJ / 5 < 0.4EJ\nBarra 4,5\nMu = 4EJ / 6 = 2EJ\nM21 = 2BJ / 6 = EJ\n2EJ\n0.8EJ\n0.4EJ\nKl1 = 2.8EJ\nKl1 = EJ\nCaso 2\nZ\nY load\nZ\nBarra 2,5\nH load\nMu = 3EJ / L\n-3EJ / 5 = 0.6EJ Barra 4,5\n[diagram]\nL = 1 a 9\nMii = 4EJ / 6 = 2EJ\nMzi = 2EJ/6 = EJ\nK12 = EJ\nK22 = 2,6EJ\n* Resolver o sistema *\n{ (p1O + K12D1 + K12D2 = 0\np2O + K22D1 + K22D2 = 0\n( -15O + 2,6D1 + K12D2 = 0\n[ 15O + 4D4 + 2,6D2 = 0\nEJ = K\nD1 = 85,98/k\nD2 = 80,46/14\nMi = 85,98 x 0,4k = 34,4 kN\nM4 (1A) = 4D x 85,78 x = 68,8 kN\nM4/3,A = 20 kN\nM4 (4,5) = 2kx 85,28 + k(-20,10) + 60 = 21,2 kN\nM5 (4,5) = 20k x (-20,16) + 85,28 k + 60 = 40,6 kN\nM5 (5,2) = 2046 - 90 = 19,6 kN D.M.F (Incompleto)\n[diagram]\n60\n21,2\n19,6\n1/n\nH2\nΣ Mh = 0 (¶)\n-62,4 + 20x6x12 + 80x3 * V2xV2=0\nV2 = 134,8 kN\n\nΣ Mz = 0\n-19,6 -134,8x3 + H2x4 = 0 → H2 = 100kN\nΣ Fy = 0\n-20x12 - 30 + 134,8 + V1=0 → V1 = 185,2 kN\nΣ Fx = 0\n-100x4 + H1 = 0 → H1 = 100kN\nsenø = 0,8\ncosø = 0,6\nMf = 106x0,8 - 134,8x0,6 = 3,92 kN\n[note]\nV14 = 185,2x0,6 - 106x0,8 = 26,32 kN\nFn14 = \n185,2 / 2,62\nFn14 = 213,4 kN D.E.W (kN)\n[diagram]\n15,94\n60\n19,4\n\nD.E.C (kN)\n[diagram]\n45,2 - x\nx = 21,2\nHmax = 51,1 - 21,2 = 30 kN\nV5 = 60 - 19,8\nV5 = 40,2 kN\n[rectangle diagram]\n20\nV = 20 x 3 + 15\nV = 60 kN\nVA = 60 - 80 + 45,2\nVF = 45,2 kN\nHmax = 45,2 * 2,62 / 2 = 51,4\n\nD.M.f (kN)\n[diagram]\n60\n21,2\n40\n10\n21,2\n19,6 Australia Short Quiz! Fun Facts\nWhat's the largest city in Australia?\nSydney\nMelbourne\nBrisbane\nPerth\nWhat is Australia's national animal?\nKoala\nKangaroo\nEmu\nPlatypus\nMultiple Answer, 25 points\nWhich two animals are on Australia's coat of arms?\nKangaroo\nEmu\nKoala\nDingo\n