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Engenharia Elétrica ·

Cálculo 4

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Sustituyendo en ② 0 uxt ddx ekx2t c1ekx c2ekx uxt c1esmx c2emx Sustituyendo en ③ 0 uLt cs mnlyekx2t v 0 0 v 0 por qALnt nZ n0 Lπk Lnt nN al final Casnnque n n gnam cuias aquivalenes fey ogo λLnt nN λπ L Wxt cs sen mx ekx2t