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Cursos Gerais ·

Hidráulica

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Nome: Raphael C. Valle\nRA: 269802033354\nPIA: Leandro Beltraco Lucio\nHidraulica Av2 Date: 37/06/2023\n\nEx1:\n\nL: 192 m\nhf: 0,00558 mm = 1,58J°\nQ: 0,197 l/s = 0,197 m³/s\nD: ?\nc: ? concretoliso\nc: H2O\n\nD = 1,625\nQ ≈ 0,197 l/s\nc = 1,585 × 10³ J°\nD = 3,33 × 10³ m\nD = 3,33 mm\nD = 3,33 mm Ex2:\n\nL: 198 m\nhf: 22,5\nAh: 50 m\nJ: ?\n\nJ = hf / L\nJ = 22,5\nJ = 0,028 m/m\n\nPressão final da tubulação = 50 MCA Ex3:\n\nL: 1,597 Km = 1597 m\nD: 60 mm = 0,06 m\nC: Ferro 60 anos de idade -> 89 e 300\nQ: 0,16972 l/h = 0,464 × 10⁻³ m³/s\nhf: ?\n\nhf = J0,643 × (c/D^4,87)\nhf = J0,643 × (4,64 × 10⁻³)^1,852 × (1,587)\n\nhf = 342,05 MCA\nhf = 342,05 MCA\nJ = hf / L\nJ = 0,090 m/m e x 4 -\nQ = 2,350 l/h + 2,235 m3/s\n\nd = 0,1% -> 0,001\nb = 70 cm -> 0,7 m\nk = 65\n\n\n\n \n \n \n\n \n\no\nk, \n\n√\n\n\n\n \n \n\n \n\n = 2,35 \n\n = 3,134\n\nAm. (b + m), h = (0,7 + 0,65).1 = 1,35 m3\n\nP = b + 2h \n\n√ \n\nh = 0.7 + 2.3.√(1 + 0,65²) = 3,03 m\n\nhu = (1,25, 0,2)\n\nn\tAm.\t1 m\tkA\tkA\tAm. kA\n\n1,3\t2,325\t3,03\t0,446\t0,584\t2,3,134\t< 2,134\n1,25\t2,0085\t3,751\t0,53555\t0,65\t1,32\t1,22\tDO.K\n1,25\t1,8966\t3,63\t0,52\t0,634\t1,13\t\n1,2\t1,776\t3,552\t0,5077\t0,63\n\n\nh = 1,25 m\n