Força Trativa Hidraulica

4 FOR\u00c7A TATIVA DE\ns = 0,002 m/m\n\n10cm\n\u03b8 = 2 cos(1 - 2 y)\n\u03b8 = 2 cos(1 - 2.8)\n10\n\u03b8 = 4.828 rad\n\nA = (A - sen \u03b8) => A = (4.428 - sen 4.768) . 0.1\u00b2\n\nA = 6,00673 m\u00b2\n\nPs = P . D\nPs = 4.428.010\n\nP = 0,221 m\n\nRH = A\nRH = 0,00673\nRH = 0,309 m\n\ng = 9800 x 2 x 0,309\n1000\n\ns = 0,602 N/m\u00b2\n\n5 PAUDE EXERC\u00cdCIO (3)\nVel = 1 m/s\n\nFH\n\ng, \u221a g*m\n\n-> PH\n\n1\n\n1\n2 29,81.0.02.0.01\n0,02\n\n\n\n 6 yC EXERCICIO 4\nVELOCIDADE = 1 m/s\n\nyc = 1,01 D^0,75\n\nD 0,26\n\nyc = 1,01 (4,58x10^-0,25)\n\n0,10 ^ 0,126\n\n\n\n\n\n\nyc = 0,085 m\n\nOnda Grota\n\nd\n\nSm = N\nm^3 = d^3\n\n66 km/h = m/s\n66 km = 1000 m = 14 = 18,33 m/s\n\n3600 s\n\n4 GN IS = K N/min\n\n4.10^4, 1 kN = 60s = 240x10^6 K W/min\n\n3 m^3/s^2 = m^5/s^3\n\n\n