Trabalho de Hidráulica

Qbc = Qab + Qac + Qaf\n\nQca = 394 l/s\nQde = Qdf (L/NF)\nQde = 1.28 QDE\nQcd = Qde + 1.28 QCE + Qfe\nQcd = 2.28 QDE\n\nQbf = 39/12.129 = QBF = 18.32 L/h\nQde = 1.28 * 1.89 QDE\nQde = 20.66 L/h\n\nPunto C:\nJfc = 10.65 * 0.085 = 0.00193 ml/mA\nAHc = 0.01 * 82.300 = 246 ml/h\n\nPunto:\nJfc = 10.65 * 0.010206 = 0.01003 ml/mA\nAHc = 0.01 * 203.200 = 246 ml/h\n\nH = 2.06 + 2.46 + 0.93 = H = 6.45 ml/h a) AH = 0.65 L/m^3, \u0394H = (4-1) = 0.65 * 0.05 \u00d7 (0.02) QR = 0.00337 ml/h\nb) V = 4.0 - 0.00(427) \u00d7 2.94 - 0.05/32 = V = 2.22 ml/mL\nc) Poly = 7.37.222^2 = Poly = 0.5 cm/h\n\nPB:\nPoly = 3.7 + 2.22 + 2.22(\n(A19 & A16^(0.85) * 20) / (A45^(1.85) * 0.05)) = Poly = 2.125 cm/h\n\nPoly max = 2.5 cm\nPoly min = 1.25 cm\n\nJac. Lace Tan 600 + 2\n9.3044 = A(0.20)^{0.6^3} = 0.02945 \u00d7 (1.28 Qh)^ 1.85 + 2\n2.004 Qh = 0.0496 g/cm^2\nQbc = 1.03 L\nQbd = 1.42 L\nVaggio = Qac + Qab = 2454 L D S T Q Q S S\n6) ∆z = ∫ f (v² + k v²) dt : (60-45) , m₉ = (f 45/10⁵ + 2.4 + 0.9 + 2.0 + 5) . v²\n= 98.2 (∆6.6 m), L f = 0.3 4\nQ = π/4 ∆² v : Q = 0.001341 m³/s\n\nb) m₉ = π . 0.0 2 v : Ψ = 1.0 m/s\n\n2g ∆z = f(L) + Kres. Zg : m₉ = (m₉(50-45) = 0.0344.45 + Kres.Zg)\n 1² (0.05)\nKres = 6H/0.4\n\n∆z = k* v² = 6410.4 (m²) : ∆z = 3.26m\n 2g\n\nLₑ = K = D. k = 6410.04. 0.05 : Lₑ= 0.93186m\n\nv = 4.0 . 000023 = 4.0 . 0.025² : Ψ = 1.0 m/s\nm²\n\n∆h = k v² = (1 + 6.94 + 0.2 + 1.1). ∆p² : ∆h = L₄m (generalized)\n\n0.388.1/40\nHₐ = H₀ + ∆Hₐ\n\nPₐly = 7 + ∆z + v² = P₂ + YZ₆ + v² + ∆Hₐ2 : 0 + ∆z + 0 + 0.50 + ∆Y²\n 2g\n\n∆z = 2.18m/s A) ∆h = 0.082 F (L∗) : 20 - 0.01827.2500.0² : Q = 0.03930 m³/s ou 39.31 l/s\n∆s 0.25\n\nCpb = Cpc + ∆hC : 542 + 0.01824.0.02.960.02392 : Cpb = 580.200 m\n0.25\n\nPₐly - C₁Pₐ = Z₁: Pₐly = 580200 - 544200\nPₐly = 36 m ou 362.8 km/l/m²