Anotação Equação de Maxwell-2021 1

fem = \int_{0}^{d} \mathbf{N}_0 B_0 \hat{a}_x \cdot (dx \hat{a}_x + dy \hat{a}_y + dz \hat{a}_z) EXEMPLO \mathbf{B} = B_0 \hat{a}_z \mathbf{\vec{v}} = -v \sin{\alpha} \hat{a}_y - v \cos{\alpha} \hat{a}_z \mathbf{E} = (\mathbf{\vec{v}}) \times B_0 \hat{a}_z \mathbf{E} = -N B_0 \sin{\alpha} \hat{a}_x Rotacional Cartesiana \nabla \times H = \left(\frac{\partial H_z}{\partial y} - \frac{\partial H_y}{\partial z}\right) \hat{a}_x + \left(\frac{\partial H_x}{\partial z} - \frac{\partial H_z}{\partial x}\right) \hat{a}_y + \left(\frac{\partial H_y}{\partial x} - \frac{\partial H_x}{\partial y}\right) \hat{a}_z Cilíndricas \nabla \times H = \frac{1}{\rho}\left(\frac{\partial (\rho H_\phi)}{\partial z} - \frac{\partial H_z}{\partial \phi}\right) \hat{a}_\rho + \left(\frac{1}{\rho}\frac{\partial H_z}{\partial \rho} \right) \hat{a}_\phi + \left(\frac{1}{\rho}\frac{\partial H_\rho}{\partial \phi} \right) \hat{a}_z Esféricas \nabla \times H = \frac{1}{r \sin \theta} \left(\frac{\partial (H_\phi \sin \theta)}{\partial \theta} - \frac{\partial H_\theta}{\partial \phi}\right) \hat{a}_r d\mathbf{E}{dt} = -d\mathbf{B} dt \mathbf{B} = B_0e^{b t} \hat{a}_z FEM DE MOVIMENTO. \mathbf{F} = Q \mathbf{E} + \mathbf{\vec{N}} x \mathbf{B} \n\varphi = \overline{q} EXEMPLO \mathbf{B} = B_0 \hat{a}_z \n\n\fem = \int_{1}^{3}\mathbf{E} \cdot d\mathbf{L} + \int_{4}^{0}\mathbf{E} \cdot d\mathbf{L} fem = \int_{0}^{d} (\mathbf{v} x B_0 \hat{a}_z) \cdot (dx \hat{a}_x + dy \hat{a}_y + dz \hat{a}_z) fem\_{basco} = \int -v B_0 \sin\alpha \vec{a_x} \cdot (dx \vec{a_x} + dy \vec{a_y} + dz \vec{a_z})\\ fem = \int_{x=b}^0 -v B_0 \sin \alpha \ dx = v B_0 b \sin \alpha\\ fem_{TOTAL} = 2 v B_0 b \sin \alpha\\ v_z = \omega r = \frac{W \alpha}{2}\\ \alpha = W t\\ fem_{TOTAL} = 2 \cdot \frac{W \alpha}{2} B_0 b \sin Wt\\ fem_{TOTAL} = W S B_0 \sin Wt\\ \\ \left\{\begin{array}{l} \omega = 2 \pi f\\ \text{VALOR RMS} = \frac{V_{PICO}}{\sqrt{2}}\\ \end{array}\right.\\ fem(RMS) = \frac{2 \pi rS B_0}{\sqrt{2}} = 4.44 r S B_0\\ Se \ N \ espiras\\ fem(RMS) = 4.44 f S B_0 N \\ \\ \text{FÓRMULA DE BOUCHEROT}