Anotação Lei de Ampere-2021 1

BOA NOITE? LEI DE AMPÈRE ∮ H→⋅dl→ = Ienlaçada Ienlaç = ∫sup J→⋅ds→ 2) PLANO INFINITO Az x y K→ = K0ay→ [A/m] H→ = Hxax→ p/g > 0 H→ = -Hxax→ p/g < 0 H→ = Hxax→ p/g > 0 H→ = K02az→ p/g > 0 H→ = -Hxax→ p/g < 0 H→ = -K02az→ p/g < 0 ∮ H→⋅dl→ = + + + = ∫1 Hxax→ (dxa x→ + dy ay→ + dz az→) + ∫3 -Hxax→ (dxa x→ + dy ay→ + dz az→) = ∫-lxl Hx dx + ∫x=l -Hx dx = Hx 2l + Hx 2l 2Hx2l = k02l Hx = K02 b) SOLENÓIDE h e ∫ H→⋅dl→ = ∫1 + ∫z + ∫3 + ∫4 = Hdl - Hdl + Hdk = 0 H→ = ∫dI→ x qq→4π(R-z)2 Hoo = 0 H = H_z a_z K = K_0 a_\varphi z = l z = 0 \oint \overrightarrow{H} \cdot d\overrightarrow{L} = \int_1^2 \overrightarrow{H} \cdot d\overrightarrow{r} + \int_2^3 \overrightarrow{H} \cdot d\overrightarrow{\varphi} + \int_3^4 \overrightarrow{H} \cdot d\overrightarrow{z} = \int_4^1 \overrightarrow{H} \cdot d\overrightarrow{L} = \int_4^1 H_z a_z \cdot (dr a_r + r d\varphi a_\varphi + dz a_z) = \int_4^1 H_z dz = \int_{z=0}^{l} H_z dz = l H_z = K_0 l \Rightarrow H_z = K_0 \overrightarrow{H} = \frac{NI}{h} a_z c) Toroide \oint \overrightarrow{H} \cdot d\overrightarrow{L} = I_{enc}. \int H_\varphi (dr a_r + r d\varphi a_\varphi + dz a_z) = \int_0^{2\pi} H_\varphi r d\varphi = 2\pi r H_\varphi 2\pi r H_\varphi = NI \Rightarrow H_\varphi = \frac{NI}{2\pi r} \overrightarrow{H} = \frac{NI}{2\pi r} a_\varphi