Resumo Teorema Rolle Lagrange Cauchy-Analise e Aplicações

x1 y1 Cases f1 k1e1 fx1 fx y hx1 x2 y2 f1 k1e1 fx1 fx1 x2 x1 Case Rolle x2 x1 fx2 fx1 fx2 fx fx2 fx1 x2 x1 fx2 fx1 x1 y 1 a x1 y x2 c fx2 fx1 fx1 e1y y e1x b f is continuous f is a fq y max e element y min c e element t lenght Lenght x2 x1 BDT fx1 fx0 e max x2 x1 heiß 2 x2 x1 2 Dose Case f prim bijv phi gx f x x x0 x x0 x x0 0 gx f x x x0 x x0 x x0 0 gx g x0 Kommutat limesxa gx gx limesxxo limesxxo fx fx0 x x0 gx x2 6 y g x0 x x n x2 n n 1 0 f x0 6 g x0 gx0 0 fx0 0 fx0 0 y 0 fx 6 y 0 form aus Imanaude cos x v 10 sin cos g g n fx n fx x 45 f arcsin y cosx y k fnx y 0 n xn1 n fx linearislvin QP Frunction linear liga Prima min fun igon Q X Q P for m 2 x2 x1 3 x ilen PRminn 1 m m 1 m prim fx2 fx1 prim fx2 fx1 p min fx1 fx max t fx max 0 fx fx max prim fx1 fom prim fx fom fx 2 fx 1 fx fx 2x 6 fx 1 2x 1 6 fx 2 2x 2 6 fx 2 fx 2x 2 6 2x 6 2m fx 2mx 6mx 2 2m fx fokt 2rx 6k 0 r 2 0 x 2x 1 f12x 2x 6 f21x 2x 6 x 1 x 2 2m 0 x a 20 x Donc 2m 0 x x 2 x 1 2m x 6 20 2m x 0 2m 0 20 x x 0 Mon au vois des nomes fonctions polina au F iN rexe 2m x I f f f f x 2m ax a b 0 a b 0 b 0 fx fx a 0 fx 0 5 2x 0 x 2 4 De 1ère Memos Stabillité pour a 2x 2 a 2 3x 3 a x a 5 x 5 y fx a x 5