Respostas

1) R = 100Ω, L = 500mH, f = 60Hz, V = 127V\n a) Xl = 2π(42. - 27100.500.10-3) = 1207.500.10-3 = 188.6Ω\n b) Z = -100.20 + j188.6.100 = -100 + j188.5Ω -> Zg1 = 21.0Ω\n c) Zl = 7 - 127.20 = -0.996 - j0.62,05 -> 191 = 0.0535A\n 100+j188.6 = 2134.67Ω\n\n2) V = 250V, f = 120Hz, R = 25H, P = 400Ω, C = 25μF\n Xl = 7.11Ω, Xc = 2/(π*120*25*10-6) = 33Ω\n Zeq = 400 + j188.9 = 63 + j187.97Ω = 18.01 + j26.28Ω\n I = 46 - 250j = 33.3 - 89.78mA\n Zeq = 8801.26/58.78\n IT1 = 13.3mA\n Vc = 9*Xc = 13.3*(-89.78) = 0.705L-172.98V\n\n3) j = 50 + 3 + j = 10L-63.13° -> -7.9* = 10 L53.13°\n Sf = 50 * 10L53.13° = 500.163.13°VA\n PP(A)out(53.13°) = 0.6\n Sf = 300 * j400\n La P = 300W\n Q = 400VA 4) Xc = √(1/(2πf*C)) = 331.57L-90Ω\n I = 710/(331.57L-90°) = 0.66L900A\n Zeq = 10 + 80j + (-j) = 10.76j = 76.66L-22.00°\n I = Zeq + Y = 120*76.66L-82.00° - 1.665L82.00A\n V1 = 1.60L292.500 - j10 -> 16.60/22.000V\n Vc = 1.066L282.500 - 74.90° = 6.682L178.200V\n Vc = 1.460L292.500 - 80.00° = 125.74L-2.49°V\n\n5) Vp: (8-6) = 32V, Vp = 16V, Vpf = 16/√2 = 11.31V\n b) Z = 20 - (10*140 mmU) = 27; E7 50m = 157.3000/ℎ\n 6) P = (average)I(P/IP) = 0.867\n I1 = (160/43)2 = 141k = 5.93K30.97°VA\n S = V * I # = 0.823L30.970/220 = 70.568.30.97° -> 87.76.6L-80.97A\n Zeq = √(2106.50.97°) = 71.1L230.97Ω\n\n7) Rp: 0 - j(-900 + j0..8 – R) = 36.87°\n Q = 36.87°\n IT1 = 100/9 = 125Ω\n Xc = 125.0L6\n Yent = 60 - C = 23.6μF 8) Zeq = 12.14 + j7 = 12.1Ω\n Zeq = R + jωL = 110.69 = 13.2Ω\n O = angle = 72.10°\n Fr = 10 + 3 - 8.46j\n\n1) V = 100.00V\n Q = -500VA -> Vd - V* - V(c) = K -> - I - Q = 0\n Q = 0.600A\n Pt = Vd(- 10) - j(v0 + i) - 900 = q2l – LQ = -1 * -Q = 90°\n I = -5.090A\n\n2) P = 900W, Vt = 100V\n Q = 500VA\n P = V*l + I + j(θ0 + θ1) - 900 = q1 + 900\n I = I1 + j(θ0 - θ1)\n Q0 = 100 - q1' tan(θ0 - θ1) - i = 5\n (factor)den(θ0 - θ1) = 5\n (θ1 - 2sin(θ0 - θ1) = 9 \n θ0 - θ1 = 29.05° imo O0 = 0° - ѱ1 = - 29,05%\nѱ1 = 2.12(31,050) - 0.9ѱ2 + ѱ6,85 = 10,06 - 19,05%\nѱ2 = 51,090A, ѱ7 = 10,59 - 19,00A\nѱr = ѱ4 + ѱr + ѱ2 = 9,26A - 0,98A\n\nS = 9,26 - 100 - 0,26A\nQ = 9,26 * JVM(10,82) = 713,714m\nP = 9,26 * JVM(0,98) - 950W\nFP = JVM(0,90) = 0,64\nQF = 713,714m\n\nIFR = 500W