Atividade 07

DSTQQSS Alvinho 09 Cap 22 Ato 09 ao 13 09 P(1) 1 + 2 + ... + n = (n + 1)/2/4 P(h) | 1 + 2 + ... + (n + 1) 3 = n |h+2 / C(n + 1) 2 (n + 2) B4 1 + 2 + 3 + ... + (n + 1) 2 = 1 + 2 + 3 + n 3 | (n + 1) 3 n + C 2 + 4 + C(n + 1) B^3 (n + 1)^2 = n 2 + n + 1 professor n + 1 | n | (n + 1) C = 1/4 S. P(n): 1 2 + 3 + ... + [2 + (n + 1) - 1] 2 = (n+1) [2 (n+1)] B P(h 1): 1 + 3x + ... + [2(h+1) - 1] 2 = (n + 1) 2B = n (2n-1) (2n+1) + [2(n+1)] 2 (n+1)[2(n-1)](2n+1) + (2n+1)2 2n + [h (2n-1) + 2n + 1] professor (2n + 1) | [2n 2 + 5 n 3] | 2(n+1) (2n+1) | [2n+1] C(n+1) [n+1] P (n+1) 11/3 DSTQQSS 10. P(1): 1 = (1 + 1) P(C2+1) C(n+1) 3-1/ 30 = d. B. 5/20 P(Cn) 1 + 2 + 4 + ... + n 3 = n | C(2n 9lCn^2 9)/10 P(Cn+1): 1 | 4 2 4 + ... + [n+1] 9 (n + 1) C(2)(C2n+1) 2+n 12 (n+1) 9 3 | C(n+1)-1/30 (n+1) [Cn+2 Cn+2 (n+1)]/20 | = (2n+1) (9 Cn+9 S) n+1 (Cn+2 + 6)(7Cn+3+9n+5)/ 20 n+1 (C6n + 3 9n 3 - 9) 2 + 9P2 + Pn + 30 70 1 + 2 + 9 + 3 ...+ (n+1) 7/ 1 + 2 + ... + = n + 4 + (n+1)^2 (n+1) = n/ 2+5 + | (3n+2) = 3n | + (n+1) 3 professor 30 n(2n+2) (9 2 + 3 9) + 30 (-) ( (n+1)3) 10 n+1 (C6n+6)n+2) - 2 + 3n+1 3 + 30 (n+1) 2 20 n + 7 (C6n 4 3 9n+3) 2 + 9 - (8n+30) 70 1 n P(9) : 1 : 3 | C(2) (9) P(Cn) : 1 : + 2 d : + ... + (C n + 2) = [ n(9)(Cn+7)]/6 P(Sz) : 1 : 2 + 2 c( 1 + : + ( Cn+1) 2(n+1;)[Cn+1)2(n+2)(h1) + n/6 1 : 1 : 2 54[(n + 11](Cn+3?) 1: 3 + 2 9 + + 2Cn+2)2 +(n+1)2(n+3) n|ln + 1| (2n+2))2-/ 6 n|2 - (n+1)2(n+3) (Cn+1)[n(Cn+7) + 6 (n^9b3) 6 n+1[ (n)2 + ]3 n |n|P n + 1 [n+2](2n+Gn)^2/ 6 = Cn 1 [n+2] 2(n 2) 2n(l(n+7)) + 2[/4 DSTQQSS 12 P(a): a + ... + a^(n-1) = (a^n - 1) / (a - 1) P(ka): 1 + a + ... + a^n = a^(n+1) - 1 1 + a + ... + a^n 1 + a + ... + a^(n^1) + a^3 a(n - 1) + a^2 + a an + 1 + a^3 (a - 1) a^(n+1) - a / a - 1