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Psicologia ·

Matemática Discreta

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D S T Q Q S S 12. P(n): 1+a+...+a^{n-1}=\frac{a^n-1}{a-1} P(k+1): 1+a+...+a^k = \frac{a^{k+1}-1}{a-1} \frac{a+a+...+a^n} 1+a+a+...+a^{n-1} + a^3 a^{n-1} + a^n + (a-1) a^{n-1- \frac{a(a-1) \frac{a-1}{a-1} e