Física 3 - 8 Lista

63. \\Lambda \\times \\rho_{p} > h\\n\\Lambda_{x} = 50.10^{-2}m = 5,0.10^{-10}m\\n\\Lambda_{0} > 6,63.10^{-24} J\\n(2h) = (2h) (5,0.10^{-10}m)\\n\\Lambda_{0} > 2,1.10^{-24} kg m/s\\n54. \\psi(y) = y_{b} e^{jsy} y_{0} e^{jktw}\\n(d^2y) = y_{0}(x,k) e^{jktw}\\n\\Rightarrow - 1^2 y_{0} w_{0} + k^{2}y=0\\n\\sqrt{y} + k^{2}y = \\rho_{y} + \\cancel{ \\gamma} \\left[\\frac{E-U}{\\phi}\\right] = 0\\n\\frac{y^2}{y_{0}} = \\frac{y}{\\sqrt{n}}\\n\\frac{y^2 \\sin y \\psi y}{ y_{0}^2 } + k^{2} \\Phi(y) = \\frac{h}{y_{0} }\\n\\sqrt{E - U(\\xi)} = h y_{1}\\n\\sqrt{y^{2}m( h - v_{1})} = h - t\\n b = \\frac{y\\gamma}{( E - U )} = y_{0}\\n\\n\\sqrt{\\frac{ \\phi y}{ (y - v_{1})} } = \\frac{y}{\\partial} 66. T = E - \\omega h\\nb = \\sqrt{y}\\gamma m( h_{0} - h)\\nh_{0} = -\\omega h\\nb = - In h\\n\\ln 2h = (J_{b} - E) = \\sqrt{\\phi m c_{} }\\nnk = h_{0} - h.\\frac{ 1}{2h^{2}}tm \\frac{ 1}{\\phi} = \\frac{1}{y} \\n\\sqrt{\\frac{ \\gamma y}{(h_{b} - h)}}= h f l = 6,626.10^{-24} J\\nt = 0.001 hT = -3 ln 10\\nm = 9,200.10^{-31} kg\\nl = 0.40 nm = 0.7.10^{-9} m\\nh = 6,00 eV = 9,612.10^{-19} m\\nE = 9,612.10^{-19} - (6,626.10^{-34} * (9.79.10^{-10}) / (39.9/9,000.10^{-31} * 0.7.10^{-9})^{2}\\nE = 19,612.10^{-19} - (4,190.10^{-19}\\nE = 0,8006.10^{-19} J = 5,072 e Vh