3 Avaliação de Física Part 4 - Evelyn Barreiros Conde

27 - 12 - 20\n∫ 0 \u2192 t (C - Q) = ∫ 0 \u2192 t \u03B4i\nQ(t) = √ C (1 - e ^( - t / RC))\n\nQ(t)\n\n√C\n\n12V R1 i₁\n12 = 12i₁ - Bi₃ - 4\n16 = 12i₁ - Bi₂\n(1)\nH + Bi₁ + 6i₂ + Bi₂ - Bi₃ - Bi₁ = 0\n-8i₁ + 22i₂ + 14i₃ = -4 (-1)\n8i₁ - 22i₂ + 14i₃ = 14\n\n6 - Hi₂ - Bi₃ - 6i₃ + 6i₂ + Bi₁ = 0\n6 - 22i₃ + 14i₁ > 0\n6 = 22i₂ - 14i₂\n\n\n Evelyn B. Condi - 2195 3688\n27 - 12 - 20\n\n16 + Bi₄ = i₁\n6 + 14i₂ = i₃\n\n1\n\nSublst na eq\u2026\n82i1 - 2i₂ + 1/4 (6 + 14i₁) = 4\n(1)\n\n32i = 16 + Bi₃ - 22i₁ + 7(6 + 14i₃) = 4\n(2)\n\n350i₁ + 76i₂ + 126i₃ + 294i₄ = 4\n350 + 72 + 29 + 350i\n(1)\n\ni₄ = 16 + 8i₄\n12\n\n\n\n\n\n\n Evelyn B. Coni - 2195 3688\n27 - 12 - 20\n\nPara P₁\n12V - 8.986V = 3.064V\nV₁ = VF = 3.06\nVₒ = 3.06 + 4 + 7.06\nP₁ = (7.06)² / 8 = 6.2 W\n\nPara P₂ e P₃\nP₃ = I²R = (I₁ - I₃)² R = (1.351 - 1.132)² . 6 = 0.28 W\nP₄ = (1.351 - 1.139)² . 8 = 0.38 W\n\nP₅ = P₆\nP = (1.132)² . 7 = 5.1 W\n\n\n