Resistência dos Materiais

DSTOOSS\n\nR: RX = 8.67\nRY = 6.75 kN\nRM = 26.24 kN.m\n\nΣFx: 0 = HA - 8.67 kN\nΣFy: RA = -7.23 + 0.5 = 0 \nRA = 6.34 kN\n\nΣM_A: -2.75 + 1.5 - 3.5 = 0 \n1.5 + 1 - 2.5 = 0 \nA_max = 26.23 kN.m DSTOOSS\n\nE_y: HA - 40 = 0 \n [HA = 40 kN]\n\nΣM_A = (23.5) + ( -1.5) + (-60.8)(-60.2) = 0 \n-135 - 225 - 150 - 480 - 0 = 750 kN DSTOOSS\n\nZ_y: 0 = HA +30 + 20 = \nHA = 50 km\n\nZ_y: 0 = RA + RB - 10 - 20 = \nRA + 51 = 50 \nRA + RB = 50 \nRB = 50 - 51 \nRB = -1 km\n\nΣM_A = (RB*0.5) + (-10.7) + (-40.2) + (-30.3) = 0 \n50 - 80 - 10 = 0 \nSRU = 255\n\nRB = 255 = RB = 51 km DSTQQSS\n\n10\n25kN/mm\n\nBulminas para o: 6.15= 40kN\n\nXT = l / 6 lb 2 = 2 m\n\nx = 3 m\n\nHA\n90kN\n30kN\n\nRA = 3.0\n1.0\n1.0\nTRo\n\nΣy = RA + RA -30- (0.3) = 0\nRA = 420\nRA = 390\n\nRA = 390 N = 65kN\n\nΣy = 0\nRA + RA - 30 = 0\nRA + RA = 420\nRA = 55 - 420\n\nmy = 1 (RA.X1 - 9.1) .x\nMY = 55 x .x\nMRA = 0\n\nJ1 = (55.0 - 25 - 2)\nJ= 0\nPARA = 0\ny = 6\nJ1 = 55.6 - 26.6\nJ1 = 3300 - 25 - 3.6\nJ1 = 55.6 - 150\noi1 = 55 - 150\nRA = 95kN\n\nJ1 = 55.20 - 0 - 0\n{\n\nX= 55 - 25\nx = 2.4kM\n\nMaximum = 60.0 kN DSTQQSS\n\nΣx = HA = 0\nΣy = RA - ql\nRA - ql = 0\nl = 2 - 0 - 1.2\nR1:: R1 - q2l\n\nRA = 6\nq2 = q3R\nx1 + x = ql\n\nΣ x2 = sum\n\nPARA - 5 = 0\ny = 10 - q\nx2 = qy - qp\n\n}{\n Σ. = q R .Model,\n r = (l - x x) \nl = q1l \n)\n\nMaximum = -3.0 + \nRA = 400496\nR1 = RA - q1;\nRA - q2 = 3.\n\nJX1:\nMRA= (PA = -R1) - 0 \nYfactor = q2 \n\nMaximum = 6;1 = -q\nJb \n\nJY = ql(x) \n\nMAXM = 9\nyn = q2l = q\nx.\n\nMAX3: 2J = -\nMY = -q1 = q2.\nM1= 0 DSTQQSS\n\nx = 6.3m\n\nΣ = -1.514\n\nΣqx = a \nRA = qx1\nq1y = RA\n\nMA = 0.\nYMS1y = 3.0.2\nRA - y (\n\nRA = QR = - 0.L\n\nPRA = equals 0\nExt = 2, qy=l, 3q1iv\nRA = 8 + MR = 0\n0 = Mq (1) + q1=0\n\nRA= - R1 + R2 + RA\nMA = 0 = 6M\nl = 60 -0 +1.5y (= 2.qx.\n\ny2\n\nl = q2 - Y a\nRA = R2 - q2*3.0 = - Y = 0\n\nRA = RM 0 = 10(ph = 3900m) } FAZ 6 km\n3x - 1 0 <= x <= 5 (estudo do) 12 >= 0\nx1 = AR - (9 - x) G = 6 - 7x\nx2 = 6 - (7 - x) 7x = 6\nx1 = 6 - y\n- PARR - x = 0\nx1 = 6 + 0\nx1 = 6 km\nx1 = 6\ny1 = (R, x) - ( 0, y, x)\n2\nx1 = 6 - 7.3\nx1 = 6 - 2.24\nx1 = - 15\ny1 = 0x1\n\n6\n6x^2 = 6x^2 - 7x (x^2 - 21)\n6x^4 - 14x^3 + 56x^2\nM(x) = 3 - 58 + 56\nPARR - 0 x = 5\n- 8.5 * 56 = 16\nPARR - 0 x = 7\n- 8.5 + 56 = 0\nUM = 0\n0 = 27 - 7y\ny = 27 - 7 = 3.85\nM = 0\n6 - 7 = 6.35\n6 - 26.95\nM = 20.95\n\n6: SUCESSO 2\nQX1 = -6 - 7( x - 2) = 0\nQX2 = -6 - 7x - 21\nQX1 = - 27 - 7x\nPARR - 0 3\n27 - 7.3\nZ1 - 71\nQX1 = 6 km\nQF = 0\nQAP = RA - 0 = 6\nQBE = RQ - 7.2 - 6 - K1 = -8\nQED = 0 - 8 + 2 = 0\nm0 = 0\nO = 29 - y + y\nY = 12\nX = 7 - 2 - 7\nX = 3.94 D S T Q 0 0 5 7 \nΣy = 0 RA = x \nΣM = 0(RB, 6) + (-40, 7) + (-14, 4) = 0 \n 6RB - 160 - 14 = 0 \n 6RB = 174 \n RB = 29 kN \n\nΣy = 0 \n RA + RB - 40 - 14 \n RA + 29 - 40 - 14 = 0 \n RA = 2 9 - 81 \n RA = 541 - 20 - RA = 25 kN \n\nSince Σx = 6 \nQx1 = RA - (9, x) \nQx1 = 25 - 7.3 \nQx1 = 25 - 21 \n\nQx1 = 14 kN \n\nCargando 0 = 0 \n - 0 = 25 - 7 \n - 7 = 13 \n x = 25 - x = 3.6 kN \n 0 - 7 - 12 \n x = 90 - 7 - 12 \n 90 - 7.5 5 \n P A R = 0 = 0 \nMxx = 25.3 - 7.3 - 3.3² \nMxx = 25 - 1.9 \n\nJ A M E = 75.3 - (3) \nJ A M A = 43 P a \n