Resistência 2

ATIVIDADE 2\n\n+ ΣF_x = 0\nH_a + H_c = 0\nH_a - H_c\nH_c = 30 kN\n\n+ ΣF_y = 0\nV_a + V_c - 60 kN = 0\nV_a = 60 kN - V_c\n\nΣM_c = 0\n\n-60 kN * 0.98 m + H_a * 0.6 m = 0\nH_a = 18 kN/m\n→ |H_a = 80 kN|\n0.6 m\n\n+ ΣF_x = 0\nH_a + H_b = 0\n80 kN + H_b = H_c\nH_b = -30 kN\n\n+ ΣF_y = 0\nV_a + V_b - 60 kN = 0\n\nA = π * (0.001 m)^2\nA = 3.14 * 10^-6 m^2\n\nN_o A:\n\n+ ΣF_x = 0\n80 kN - F_A = 0\nF_A = -80 kN\n\nN_o V:\nF_c\nF_c(y)\n0.6 m\n0.9 m\n\nF_c(y) = 0.975\nα = 36.87°\nF_c = F_c(x)\n\n+ ΣF_x = 0\n(-80 kN) - F_gc = 0\nF_gc = 80 kN\n\n+ ΣF_y = 0\nΣT_c = V / A = 10000 / 2\n3.14 * 10^-6 m^2\n\nT_c = 159 235 668.3 N/m² = 159.21 MPa Cx 80,0\nCy 60,0\n\nAx 80,0\nAy 0,0\n\nB\nC\nT = 100,0\nC = 80,0\n\nA\nB\n60,0