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Engenharia Civil ·

Resistência dos Materiais

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Obs: Abrangências importantes Na seção a-a fc = Naa = 15 kN Vaa = 0 Aaa = (35)(39) = 1.225 logo, em a-a Naa = 15 kN Vaa = 0 Aaa = 1.225 mm² Tmed aa = Vaa / Aaa -> Tmed aa = 0/1.225 = 0 MPa omed aa = Naa / Aaa -> omed aa = 15/1.225 -> 15 (1000) / 1.225 mm² ------> omed aa = 12.2 MPa Na seção b-b Frey = Vbb = 32 kN Fbcx = Nbb = 9 kN obs: Frey = Vbb = 32 kN Fbcx = Nbb = 9 kN Encontrar a linha a bb SEN(b) = 35/l -> L = 35 / SEN(b) -> L = 35/SEN(36.87) L = 58.33 mm Abb = 35.L -> Abb = (35)(58.33) Abb = 2.041,55 mm²